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Range Over Ticker In Go With Immediate First Tick

The Go standard library has a really cool type – Ticker. Tickers are used when you want to do something at a regular interval, similar to JavaScript’s setInterval. Here’s an example:

package main import ( "fmt" "time" ) func main() { ticker := time.NewTicker(time.Second) go func() { for range ticker.C { fmt.Println("Tick") } }() time.Sleep(time.Second * 4) ticker.Stop() fmt.Println("Ticker stopped") }
Code language: Go (go)

As per the docs, a ticker is a struct that holds a receive-only channel of time.Time objects.

type Ticker struct { C <-chan Time // The channel on which the ticks are delivered. }
Code language: Go (go)

In the example at the beginning of the article, you will notice by running the program that the first tick sent over the channel happens after the first interval of time has elapsed. As such, if you are trying to build, for example, a rate limiter, it can be inconvenient because to get the first immediate execution, it would seem your best option is:

func doSomethingWithRateLimit() { ticker := time.NewTicker(time.Second) doSomething() for range ticker.C { doSomething() } }
Code language: Go (go)

There is in fact a better option!

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In Go, a channel can also be iterated over in a normal for-loop, so our solution is to build a for loop that executes automatically on the first iteration, then waits for each subsequent loop.

package main import ( "fmt" "time" ) func main() { ticker := time.NewTicker(time.Minute) for ; true; <-ticker.C { fmt.Println("hi") } }
Code language: Go (go)

Hopefully this helps keep redundant code out of your projects!

Have questions or feedback?

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